4*10^2y=3600

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Solution for 4*10^2y=3600 equation:



4*10^2y=3600
We move all terms to the left:
4*10^2y-(3600)=0
Wy multiply elements
40y^2-3600=0
a = 40; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·40·(-3600)
Δ = 576000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{576000}=\sqrt{57600*10}=\sqrt{57600}*\sqrt{10}=240\sqrt{10}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{10}}{2*40}=\frac{0-240\sqrt{10}}{80} =-\frac{240\sqrt{10}}{80} =-3\sqrt{10} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{10}}{2*40}=\frac{0+240\sqrt{10}}{80} =\frac{240\sqrt{10}}{80} =3\sqrt{10} $

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